Sequences: Homework Matchsticks
marking scheme  table
Marking scheme
Marking points will be allocated thus:
 6 points presentation for:
 large table
 easy to read
 colour
 photographs of matchstick diagrams, not just rough drawings.
 4 points completeness for:
 a reasonable number of rows in the table, like 5 or 6
 a row in the table for the generic case
 a row in the table for a high matchstick count
 a check column
 10 points accuracy and working for:
 clearly showing working and calculations
 correct formula
 checking formula actually works for first few values
 application of formula for number(s) outside the first few
that are easily countable
Table
n 
diagram 
matchstick count 
formula 
check 
1 

horizontal = 2
vertical = 2
total = 4 
2n(n+1) 
2 * 1 * 2 = 4 √ 
2 

horizontal = 2 * 3 = 6
(2 matches in each of 3 rows)
vertical = 2 * 3 = 6
(2 matches in each of 3 columns)
total = 12 
2n(n+1) 
2 * 2 * 3 = 12 √ 
3 

horizontal = 3 * 4 = 12
(3 matches in each of 4 rows)
vertical = 3 * 4 = 12
(3 matches in each of 4 columns)
total = 24 
2n(n+1) 
2 * 3 * 4 = 24 √ 
4 

horizontal = 4 * 5 = 20
(4 matches in 5 rows)
vertical = 4 * 5 = 20
(4 matches in 5 columns)
total = 40 
2n(n+1) 
2 * 4 * 5 = 40 √ 
5 

horizontal = 5 * 6 = 30
(5 matches in each of 6 rows)
vertical = 5 * 6 = 30
(5 matches in each of 6 columns)
total = 60 
2n(n+1) 
2 * 5 * 6 = 60 √ 
6 

horizontal = 6 * 7
(6 matches in each of 7 rows)
vertical = 6 * 7
(6 matches in each of 7 columns)
total = 84 
2n(n+1) 
2 * 6 * 7 = 84 √ 
100 
(To count the matches,
click for a larger version.) 
lots 
2n(n+1) 
2 * 100 * 101
= 202 * 100
= 20,200 
There are several ways the formula could be written. The first is probably
the easiest to compute in one's head.
f(n) = 2n(n + 1)
f(n) = 2(n^{2} + n)
f(n) = 2n^{2} + 2n
Another way to work out the number of matches used would be to count
the number of squares, then subtract the number of matches from those
squares that would be doubled up.
4 matches in each of n * n squares
∴ matches in squares = 4n^{2}
n matches doubled up in each of (n1) rows = n(n1)
n matches doubled up in each of (n1) columns = n(n1)
∴ matches doubled up = 2n(n1)
∴ total matches = 4n^{2}  2n(n1)
= 4n^{2}  (2n^{2}  2n)
= 4n^{2}  2n^{2} + 2n
= 2n^{2} + 2n
= 2n(n+1)
Not surprisingly, it comes out with the same formula.
